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x^2-1002-2000=0
We add all the numbers together, and all the variables
x^2-3002=0
a = 1; b = 0; c = -3002;
Δ = b2-4ac
Δ = 02-4·1·(-3002)
Δ = 12008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12008}=\sqrt{4*3002}=\sqrt{4}*\sqrt{3002}=2\sqrt{3002}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{3002}}{2*1}=\frac{0-2\sqrt{3002}}{2} =-\frac{2\sqrt{3002}}{2} =-\sqrt{3002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{3002}}{2*1}=\frac{0+2\sqrt{3002}}{2} =\frac{2\sqrt{3002}}{2} =\sqrt{3002} $
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